On Mon, Dec 09, 2024 at 11:37:33AM +0000, Ricardo G. Herdt wrote: > Hi Jeremy, > > Am 09.12.2024 11:21 schrieb Jeremy Korwin-Zmijowski: > > The reference says : > > > > Scheme Procedure: *sorted?* items less > > C Function: *scm_sorted_p* (items, less) > > > > Return |#t| if items is a list or vector such that, for each > > element x and the next element y of items, |(less y x)| returns > > |#f|. Otherwise return |#f|. > > > > I think the description should be : > > > > Return |#t| if items is a list or vector such that, for each element > > x and the next element y of items, |(less y x)| returns |#t|. > > Otherwise return |#f|. > > Actually no, since less is applied to y and x in that order. This way > (sorted? '(1 1) <) correctly returns #t as your experiments show.
I don't get it. (< 1 1) is /always/ #f, regardless of the order of the ones? I'm as confused as Jeremy is. Cheers -- tomás
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