Do you mean encoding should be
rawdata := fmt.Print("%016d%s%s", len(s1), s1,s2)
or
rawdata := fmt.Printf("%016d%s%s", len(s1), s1,s2)
On Monday, March 13, 2023 at 4:36:50 PM UTC+2 Alex Howarth wrote:
> You might be looking for strconv.ParseUint()
> https://pkg.go.dev/strconv#ParseUint
>
> https://go.dev/play/p/qAO9LfLD41D
>
> On Mon, 13 Mar 2023 at 07:24, Van Fury <fury...@gmail.com> wrote:
>
>>
>> Sorry I did not frame my question properly but what I would like to do is
>> to
>> encode concatenated s1 and s2 into raw binary and then decode the raw
>> binary
>> back to s1 and s2.
>>
>>
>> On Friday, March 10, 2023 at 11:36:09 PM UTC+2 Alex Howarth wrote:
>>
>>> If s1 and s2 are a fixed length then you can just slice up the decoded
>>> string based on the lengths. If they are of a variable length, you'll need
>>> a separator in the input string to later split on when decoded (s3 := s1 +
>>> ":" + s2 etc)?
>>>
>>> On Fri, 10 Mar 2023 at 10:33, Van Fury <fury...@gmail.com> wrote:
>>>
>>>> Hi,
>>>>
>>>> I have two hexadecimal string values and would like to concatenate the
>>>> two strings and
>>>>
>>>> 1. encode the result to binary
>>>> 2. decode the resulting binary back to hexadecimal string
>>>>
>>>> I did the following but I was finding it difficult to decode the result
>>>> back. I ignore error check in this case.
>>>>
>>>> What i did so far:
>>>>
>>>> s1 := "1d28ed66824aa2593e1f2a4cf740343f"
>>>>
>>>> s2 := "dee2bd5dde763885944bc9d65419"
>>>>
>>>> s3 := s1 + s2
>>>>
>>>> s1s2Byte, _ := hex.DecodeString(s3)
>>>>
>>>> randAutnBin := fmt.Sprintf("%b", s1s2Byte)
>>>>
>>>> result:
>>>>
>>>> [11101 101000 11101101 1100110 10000010 1001010 10100010 1011001 111110
>>>> 11111 101010 1001100 11110111 1000000 110100 111111 11011110 11100010
>>>> 10111101 1011101 11011110 1110110 111000 10000101 10010100 1001011
>>>> 11001001
>>>> 11010110 1010100 11001]
>>>>
>>>> I would like to decode the binary result back the hexadecimal string to
>>>> get s1 and s2.
>>>>
>>>> Any help?
>>>>
>>>> Van
>>>>
>>>> --
>>>>
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>>>>
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