It depends then, because technically the Go RW lock queues readers behind a
waiting writer so “busy” is somewhat undefined. If “busy” means “would block”
you can still do it - I’ll post the code tonight.
> On Dec 3, 2019, at 6:49 PM, Robert Engels <reng...@ix.netcom.com> wrote:
>
> I would use an atomic and a lock instead of two locks.
>
>>> On Dec 3, 2019, at 6:35 PM, burak serdar <bser...@computer.org> wrote:
>>>
>>> On Tue, Dec 3, 2019 at 5:21 PM Liam Breck <networkimp...@gmail.com> wrote:
>>>
>>> I have a problem that is trivially solved via
>>>
>>> door sync.RWMutex
>>>
>>> func Reader() T {
>>> if !door.TryRLock() { // missing in stdlib :-(
>>> return busy
>>> }
>>> defer door.RUnlock()
>>> ...
>>> }
>>>
>>> func Writer() {
>>> door.Lock()
>>> defer door.Unlock()
>>> ...
>>> }
>>>
>>> How does one achieve this in Go?
>>
>> Two locks and a bool?
>>
>> var door=sync.Mutex{}
>> var x=sync.Mutex{}
>> var b bool
>>
>> func trylock() bool {
>> x.Lock()
>> if b {
>> x.Unlock()
>> return false
>> }
>> b=true
>> door.Lock()
>> x.Unlock()
>> return true
>> }
>>
>> unlock:
>>
>> x.Lock()
>> b=false
>> door.Unlock()
>> x.Unlock()
>>
>>
>>
>>
>>>
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>>
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