Erm... not seeing how cas works to try a read-lock, which admits multiple
callers...
On Tuesday, December 3, 2019 at 5:12:08 PM UTC-8, Robert Engels wrote:
>
> Can’t code on the phone but a cas on the atomic then take the lock. But if
> you never need to block you don’t even need the lock.
>
> On Dec 3, 2019, at 6:52 PM, Liam Breck <networ...@gmail.com <javascript:>>
> wrote:
>
>
> Which looks like...?
>
> On Tue, Dec 3, 2019, 4:50 PM Robert Engels <ren...@ix.netcom.com
> <javascript:>> wrote:
>
>> I would use an atomic and a lock instead of two locks.
>>
>> > On Dec 3, 2019, at 6:35 PM, burak serdar <bse...@computer.org
>> <javascript:>> wrote:
>> >
>> > On Tue, Dec 3, 2019 at 5:21 PM Liam Breck <networ...@gmail.com
>> <javascript:>> wrote:
>> >>
>> >> I have a problem that is trivially solved via
>> >>
>> >> door sync.RWMutex
>> >>
>> >> func Reader() T {
>> >> if !door.TryRLock() { // missing in stdlib :-(
>> >> return busy
>> >> }
>> >> defer door.RUnlock()
>> >> ...
>> >> }
>> >>
>> >> func Writer() {
>> >> door.Lock()
>> >> defer door.Unlock()
>> >> ...
>> >> }
>> >>
>> >> How does one achieve this in Go?
>> >
>> > Two locks and a bool?
>> >
>> > var door=sync.Mutex{}
>> > var x=sync.Mutex{}
>> > var b bool
>> >
>> > func trylock() bool {
>> > x.Lock()
>> > if b {
>> > x.Unlock()
>> > return false
>> > }
>> > b=true
>> > door.Lock()
>> > x.Unlock()
>> > return true
>> > }
>> >
>> > unlock:
>> >
>> > x.Lock()
>> > b=false
>> > door.Unlock()
>> > x.Unlock()
>> >
>> >
>> >
>> >
>> >>
>> >> --
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>> .
>> >
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>>
>>
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