在 2019年7月31日星期三 UTC+8下午12:08:51，Ian Lance Taylor写道： > > On Tue, Jul 30, 2019 at 8:58 PM <wangjin...@gmail.com <javascript:>> > wrote: > > > > I read go runtime code，but I'm poor in assembly language, > > i can't understand the following code > > // switch to g0 > > MOVQ DX, g(CX) > > MOVQ (g_sched+gobuf_sp)(DX), BX > > // make it look like mstart called systemstack on g0, to stop > traceback > > SUBQ $8, BX > > MOVQ $runtime·mstart(SB), DX > > MOVQ DX, 0(BX) > > MOVQ BX, SP > > > > > > what does copy runtime·mstart to stack means,could someone help me > > It does exactly what the comment says: when doing a stack traceback, > it makes it appear that mstart called systemstack. When a function is > called, the return address is placed on the stack. In this case the > assembly code is deliberately putting mstart on the stack, so that > that is what a traceback will see. > > Ian >
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