On Tue, Jul 30, 2019 at 8:58 PM <wangjinjinj...@gmail.com> wrote: > > I read go runtime code，but I'm poor in assembly language, > i can't understand the following code > // switch to g0 > MOVQ DX, g(CX) > MOVQ (g_sched+gobuf_sp)(DX), BX > // make it look like mstart called systemstack on g0, to stop > traceback > SUBQ $8, BX > MOVQ $runtime·mstart(SB), DX > MOVQ DX, 0(BX) > MOVQ BX, SP > > > what does copy runtime·mstart to stack means,could someone help me
It does exactly what the comment says: when doing a stack traceback, it makes it appear that mstart called systemstack. When a function is called, the return address is placed on the stack. In this case the assembly code is deliberately putting mstart on the stack, so that that is what a traceback will see. Ian -- You received this message because you are subscribed to the Google Groups "golang-nuts" group. To unsubscribe from this group and stop receiving emails from it, send an email to golang-nuts+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/golang-nuts/CAOyqgcUBAfeQuOKfnvvxhXeQcFZMkETF4s3GseDevmQyk5Mjnw%40mail.gmail.com.
