Oh! Yeah, that's never going to work. How could it?
On Mon, 2018-12-10 at 13:43 -0800, Tyler Compton wrote:
> If my interpretation of the question is correct, I think it boils
> down to
> whether or not it's possible to get the reflect.Type of a type in
> order to
> pass it to a function without first creating an instance of that
> type. I
> don't think it's possible but I would be interested to hear from
> someone
> who knows more.
>
> On Mon, Dec 10, 2018 at 1:28 PM Dan Kortschak <d...@kortschak.io>
> wrote:
>
> >
> > No, it is possible, but you need to pass the pointer to the
> > interface.
> > You can then use reflect to interrogate the interface value.
> >
> > The bigger question, and one that would help here would be what is
> > it
> > that you are actually trying to achieve.
> >
> > On Mon, 2018-12-10 at 08:53 -0600, Mark Volkmann wrote:
> > >
> > > Yes, this is what I'm trying to do!
> > > Perhaps this is not possible.
> > >
> > > On Sun, Dec 9, 2018 at 10:34 PM Robert Engels <rengels@ix.netcom.
> > > com>
> > > wrote:
> > >
> > > >
> > > >
> > > > I think what the OP wants is:
> > > >
> > > > type A interface{}
> > > > type B interface{}
> > > >
> > > > ...
> > > > PrintInterface(A)
> > > >
> > > > Meaning they want to pass the interface definition to some
> > > > method.
> > > >
> > > > At least that’s what I am guessing.
> > > >
> > > > On Dec 9, 2018, at 9:22 PM, Space A. <reexist...@gmail.com>
> > > > wrote:
> > > >
> > > > reflect/* is a bit tricky. Use pointer to get interface itself.
> > > >
> > > > package main
> > > >
> > > > import (
> > > > "fmt"
> > > > "reflect"
> > > > )
> > > >
> > > > func main() {
> > > > test := interface{}("test")
> > > > printInterfaceValue(test)
> > > > }
> > > >
> > > > func printInterfaceValue(i interface{}) {
> > > > switch testing := i.(type) {
> > > > case interface{}:
> > > > fmt.Println("is interface, with value:", testing)
> > > > case string:
> > > > fmt.Println("is not interface")
> > > > }
> > > >
> > > > fmt.Println("reflect.Type is", reflect.TypeOf(&i).Elem())
> > > > }
> > > >
> > > > Output:
> > > >
> > > > is interface, with value: test
> > > > reflect.Type is interface {}
> > > >
> > > >
> > > >
> > > >
> > > >
> > > >
> > > > понедельник, 10 декабря 2018 г., 5:05:12 UTC+3 пользователь
> > > > Robert
> > > > Engels
> > > > написал:
> > > > >
> > > > >
> > > > >
> > > > > I mean reflect.Type not a type that is an interface.
> > > > >
> > > > > On Dec 9, 2018, at 6:53 PM, Space A. <reexi...@gmail.com>
> > > > > wrote:
> > > > >
> > > > > Of course. When you "pass a value whose type implements the
> > > > > interface" as
> > > > > an interface argument to a function, you in fact pass an
> > > > > *interface*.
> > > > >
> > > > >
> > > > > воскресенье, 9 декабря 2018 г., 23:23:41 UTC+3 пользователь
> > > > > Mark
> > > > > Volkmann
> > > > > написал:
> > > > > >
> > > > > >
> > > > > >
> > > > > > Is it possible to pass an interface to a function in Go? I
> > > > > > don’t want to
> > > > > > pass a value whose type implements the interface, I want to
> > > > > > pass the
> > > > > > interface.
> > > > > >
> > > > > > --
> > > > > > R. Mark Volkmann
> > > > > > Object Computing, Inc.
> > > > > >
> > > > > --
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> > > R. Mark Volkmann
> > > Object Computing, Inc.
> > >
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