If my interpretation of the question is correct, I think it boils down to
whether or not it's possible to get the reflect.Type of a type in order to
pass it to a function without first creating an instance of that type. I
don't think it's possible but I would be interested to hear from someone
who knows more.
On Mon, Dec 10, 2018 at 1:28 PM Dan Kortschak <d...@kortschak.io> wrote:
> No, it is possible, but you need to pass the pointer to the interface.
> You can then use reflect to interrogate the interface value.
>
> The bigger question, and one that would help here would be what is it
> that you are actually trying to achieve.
>
> On Mon, 2018-12-10 at 08:53 -0600, Mark Volkmann wrote:
> > Yes, this is what I'm trying to do!
> > Perhaps this is not possible.
> >
> > On Sun, Dec 9, 2018 at 10:34 PM Robert Engels <reng...@ix.netcom.com>
> > wrote:
> >
> > >
> > > I think what the OP wants is:
> > >
> > > type A interface{}
> > > type B interface{}
> > >
> > > ...
> > > PrintInterface(A)
> > >
> > > Meaning they want to pass the interface definition to some method.
> > >
> > > At least that’s what I am guessing.
> > >
> > > On Dec 9, 2018, at 9:22 PM, Space A. <reexist...@gmail.com> wrote:
> > >
> > > reflect/* is a bit tricky. Use pointer to get interface itself.
> > >
> > > package main
> > >
> > > import (
> > > "fmt"
> > > "reflect"
> > > )
> > >
> > > func main() {
> > > test := interface{}("test")
> > > printInterfaceValue(test)
> > > }
> > >
> > > func printInterfaceValue(i interface{}) {
> > > switch testing := i.(type) {
> > > case interface{}:
> > > fmt.Println("is interface, with value:", testing)
> > > case string:
> > > fmt.Println("is not interface")
> > > }
> > >
> > > fmt.Println("reflect.Type is", reflect.TypeOf(&i).Elem())
> > > }
> > >
> > > Output:
> > >
> > > is interface, with value: test
> > > reflect.Type is interface {}
> > >
> > >
> > >
> > >
> > >
> > >
> > > понедельник, 10 декабря 2018 г., 5:05:12 UTC+3 пользователь Robert
> > > Engels
> > > написал:
> > > >
> > > >
> > > > I mean reflect.Type not a type that is an interface.
> > > >
> > > > On Dec 9, 2018, at 6:53 PM, Space A. <reexi...@gmail.com> wrote:
> > > >
> > > > Of course. When you "pass a value whose type implements the
> > > > interface" as
> > > > an interface argument to a function, you in fact pass an
> > > > *interface*.
> > > >
> > > >
> > > > воскресенье, 9 декабря 2018 г., 23:23:41 UTC+3 пользователь Mark
> > > > Volkmann
> > > > написал:
> > > > >
> > > > >
> > > > > Is it possible to pass an interface to a function in Go? I
> > > > > don’t want to
> > > > > pass a value whose type implements the interface, I want to
> > > > > pass the
> > > > > interface.
> > > > >
> > > > > --
> > > > > R. Mark Volkmann
> > > > > Object Computing, Inc.
> > > > >
> > > > --
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> > > >
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> >
> > --
> > R. Mark Volkmann
> > Object Computing, Inc.
> >
>
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--
Tyler Compton
Student of Software Engineering
Arizona State University
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