I tried all those options; it generates the below error. gpg: fatal: too many random bits requested; the limit is 4799 secmem usage: 3008/3008 bytes in 5/5 blocks of pool 3200/16384
Any clues? -----Original Message----- From: gnupg-users-boun...@gnupg.org [mailto:gnupg-users-boun...@gnupg.org] On Behalf Of Daniel Kahn Gillmor Sent: Sunday, January 08, 2012 1:57 PM To: gnupg-users@gnupg.org Subject: Re: Encryption with key ID On 01/06/2012 09:30 PM, Hauke Laging wrote: > Am Samstag, 7. Januar 2012, 01:41:48 schrieb remesh_chan...@dell.com: >> pub 1024D/5XXXXX11 2005-08-08 ABC DEF GHI sub 6000g/99999993 >> 2011-01-01 >> >> We are used to encrypting by providing the email account reference in >> the -recipient option. Since this one just has a phrase (ABC DEF >> GHI), we are unable to do so. The vendor's suggestion is to use their >> key id >> (0x5XXXXX11) to do the encryption. Is this possible? If yes, what is >> the command to do so? > > gpg --encrypt --recipient 5XXXXX11 file.txt gpg --encrypt --recipient > "ABC DEF GHI" file.txt gpg --encrypt --recipient > D44C6A5B71B0427CCED3025CBD7D6D27ECCB5814 file.txt (with the key's > fingerprint instead of mine, of course) even better, if you prefix the keyID with 0x gpg will automatically interpret it as such. Read the "HOW TO SPECIFY A USER ID" section in the gpg manpage for more details. Regards, --dkg _______________________________________________ Gnupg-users mailing list Gnupg-users@gnupg.org http://lists.gnupg.org/mailman/listinfo/gnupg-users
