The beginning of the loop ensures that slash can never be NULL. So
don't keep checking whether it is NULL later in the loop.
Furthermore, there is no need for an early
return it;
from the loop if slash points at the end of the string, because that
is exactly what will happen when the while condition fails at the
start of the next iteration.
Helped-by: David Kastrup <d...@gnu.org>
Signed-off-by: Michael Haggerty <mhag...@alum.mit.edu>
---
I incorporated David's suggestion, and then realized that yet another
check was superfluous, so I removed that one too.
cache-tree.c | 15 ++++++---------
1 file changed, 6 insertions(+), 9 deletions(-)
diff --git a/cache-tree.c b/cache-tree.c
index 0bbec43..19252c3 100644
--- a/cache-tree.c
+++ b/cache-tree.c
@@ -551,25 +551,22 @@ static struct cache_tree *cache_tree_find(struct
cache_tree *it, const char *pat
if (!it)
return NULL;
while (*path) {
- const char *slash;
struct cache_tree_sub *sub;
+ const char *slash = strchr(path, '/');
- slash = strchr(path, '/');
if (!slash)
slash = path + strlen(path);
- /* between path and slash is the name of the
- * subtree to look for.
+ /*
+ * Between path and slash is the name of the subtree
+ * to look for.
*/
sub = find_subtree(it, path, slash - path, 0);
if (!sub)
return NULL;
it = sub->cache_tree;
- if (slash)
- while (*slash && *slash == '/')
- slash++;
- if (!slash || !*slash)
- return it; /* prefix ended with slashes */
path = slash;
+ while (*path == '/')
+ path++;
}
return it;
}
--
1.9.0
--
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