On 7/11/2023 3:03 PM, John Smith wrote:
Thanks for responding, Elliot. I somewhat understand that after the write is accomplished, the returning packet won't have the data. But still, why is the returned value 0 in that case? Shouldn't it still be equal to the memory access latency.
In the Atomic case this code is assuming the write can be absorbed into a write buffer, so there is no additional latency visible to the user. Of course it is *possible* to saturate the buffers, and if you want a more accurate accounting you can use a Timing model instead. EM _______________________________________________ gem5-users mailing list -- gem5-users@gem5.org To unsubscribe send an email to gem5-users-le...@gem5.org