On Mon, Oct 11, 2021 at 2:51 AM David Malcolm <dmalc...@redhat.com> wrote:
>
> On Sun, 2021-10-10 at 23:04 +0530, Shubham Narlawar via Gcc wrote:
> > Hello,
> >
> > Is there a direct way to print the name of the function call in gimple
> > call
> > statement?
> >
> > For example -
> >
> > void bar() {
> > a = foo(); //gimple* stmt
> > }
> >
> > I want to print "foo" from the above gimple*.
> >
> > I traced debug_gimple_stmt(gimple*) but it seems complex to just print
> > "foo".
>
> Bear in mind that not every gimple call is calling a specific function;
> it could be a jump through a function pointer.
>
> tree fn_ptr = gimple_call_fn (call);
>
> However, for simple cases like the above, fn_ptr will be an ADDR_EXPR
> node, and the zeroth operand of the ADDR_EXPR node will get you the
> fndecl (of "foo").
> tree fn_decl = TREE_OPERAND (fn_ptr, 0);
>
> Given a decl, you can then use:
> tree identifier = DECL_NAME (fn_decl);
> to get the identifier node for the decl ("foo").
>
> Finally, you can use
> const char *str = IDENTIFIER_POINTER (identifier)
> to get a 0-terminated string from the identifier that you can print.
>
> Hope this is helpful
This is helpful! Thank you David for the detailed explanation. This is
exactly what I was looking for. Now, I am able to get the function
name using above checks.
Regards,
Shubham
> Dave
>
