Re: Why does printing a pointer cause it to escape?

[Erick Ochoa via Gcc]

Hi Liu,

thanks, this also seems correct. I originally thought that (in your
example) ptr would be marked as pointing to { ESCAPE NONLOCAL } and
that would be enough to hinder some optimizations that might influence
variable value. Therefore, it wasn't necessary to mark "value" as
pointing to { ESCAPE NONLOCAL }. But now I see that that's not the
case and value needs to also point to { ESCAPE NONLOCAL }.

Thanks!