On Sun, Apr 30, 2017 at 11:56 PM, Freddie Chopin <freddie_cho...@op.pl> wrote:
> Hello!
>
> A code that I wrote was warning-free in GCC 4.9, GCC 5 and GCC 6. It
> was also warning-free with some older GCC 7 experimental snapshots (for
> example 7-20170409). But in the most recent snapshot (including the
> first RC), it started to produce a warning about aliasing. The code
> basically boils down to this:
>
> -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 --
>
> #include <type_traits>
>
> std::aligned_storage<sizeof(int), alignof(int)>::type storage;
>
> int main()
> {
>     *reinterpret_cast<int*>(&storage) = 42;
> }
>
> -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 --
>
> Compilation with latest GCC 7 RC:
>
> -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 --
>
> $ g++ -Wall -O2 -c main.cpp
> main.cpp: In function 'int main()':
> main.cpp:7:34: warning: dereferencing type-punned pointer will break
> strict-aliasing rules [-Wstrict-aliasing]
>   *reinterpret_cast<int*>(&storage) = 42;
>
> -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 --
>
> (interesting observation is that the warning is not produced when
> optimizations are disabled)
>
> Compilation with GCC 6 gives no warnings at all.
>
> Now I'm wondering, the code above definitely HAS type-punning, no
> question about that, but isn't std::aligned_storage meant to be used
> that way?
>
> For instance the example code given here on cppreference generally
> produces no warning with GCC 7 but only because:
> - std::string somehow is not affected,
> - std::aligned_storage is accessed with an offset.
>
> http://en.cppreference.com/w/cpp/types/aligned_storage
>
> By changing std::string into int, removing offset access to
> std::aligned_storage and removing irrelevant parts you get this:
>
> -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 --
>
> #include <iostream>
> #include <type_traits>
> #include <string>
>
> template<class T, std::size_t N>
> class static_vector
> {
>     // properly aligned uninitialized storage for N T's
>     typename std::aligned_storage<sizeof(T), alignof(T)>::type data[N];
>     std::size_t m_size = 0;
>
> public:
>
>     // Access an object in aligned storage
>     const T& operator[](std::size_t pos) const
>     {
>         return *reinterpret_cast<const T*>(data/*+pos*/); // <- note
> here, offset access disabled
>     }
> };
>
> int main()
> {
>     static_vector<int, 10> v1;
>     std::cout << v1[0] << '\n' << v1[1] << '\n';
> }
>
> -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 --
>
> And this produces exactly the same warning:
>
> -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 --
>
> main.cpp: In instantiation of 'const T& static_vector<T,
> N>::operator[](std::size_t) const [with T = int; unsigned int N = 10;
> std::size_t = unsigned int]':
> main.cpp:24:22:   required from here
> main.cpp:17:16: warning: dereferencing type-punned pointer will break
> strict-aliasing rules [-Wstrict-aliasing]
>          return *reinterpret_cast<const T*>(data/*+pos*/);
>                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
>
> -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 -- >8 --
>
> So my question is - is this a bug or a feature?

First of all the -Wstrict-aliasing warning is not very accurate.  But this shows
an issue with GCC 7 so please open a bugreport.  Testcase without libstd++
headers:

template<unsigned _Len, unsigned _Align>
struct aligned_storage
{
  union type
    {
      unsigned char __data[_Len];
      struct __attribute__((__aligned__((_Align)))) { } __align;
    };
};

aligned_storage<sizeof(int), alignof(int)>::type storage;

int main()
{
  *reinterpret_cast<int*>(&storage) = 42;
}

and we warn from

525                   && (set1 == 0
526                       || (!alias_set_subset_of (set2, set1)
527                           && !alias_sets_conflict_p (set1, set2))))
528                 {
529                   warning (OPT_Wstrict_aliasing, "dereferencing
type-punned "
530                            "pointer will break strict-aliasing rules");
531                   return true;

where set1 == 0 (of 'storage') and set2 == 1 (of 'int').  Not sure why we warn
if set1 == 0 ...

Richard.

> Thanks in advance!
>
> Regards,
> FCh
>
> BTW - I've also posted this question on stackoverflow
> http://stackoverflow.com/questions/43711567/gcc-7-aligned-storage-and-dereferencing-type-punned-pointer-will-break-strict

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