I just noticed that the C and C++ compiler output pointer types differently:
Consider int i; printf("%p", &i); When compiled as C that gives the warning format '%p' expects argument of type 'void *', but argument 2 has type 'int *' but when compiled as C++ it gives the warning format '%p' expects argument of type 'void*', but argument 2 has type 'int*' Why are they different? /MF