On Tue, Dec 8, 2015 at 3:35 PM, Richard Biener
<richard.guent...@gmail.com> wrote:
> On Tue, Dec 8, 2015 at 3:22 PM, Uday P. Khedker <u...@cse.iitb.ac.in> wrote:
>>
>>
>> Richard Biener wrote on 12/03/2015 03:32 PM:
>>>
>>> On Thu, Dec 3, 2015 at 8:54 AM, Uday P. Khedker <u...@cse.iitb.ac.in>
>>> wrote:
>>>>
>>>> We are implementing points-to analysis in GCC 4.7.2 and need to
>>>> distinguish
>>>> between
>>>> pointers to scalars and the pointers to structures. This distinction by
>>>> using the TYPE (TREE_TYPE)
>>>> hierarchy of the tree node of the pointer. We have two questions:
>>>>
>>>> (a) Is it sufficient to check for the presence of RECORD_TYPE in type
>>>> hierarchy?
>>>> (b) Is it safe to assume that the RECORD_TYPE always appears as a leaf
>>>> node
>>>> in
>>>>      the type description of any pointer to structure?
>>>>
>>>> As an example, the tree nodes of a pointer to an integer (y) and a
>>>> pointer
>>>> to a structure (f)
>>>> below. It seems to support our hunch.
>>>
>>> Yes, your observations are correct with respect to types.
>>>
>>> But you can't rely on the pointer type for determining what kind of
>>> object apointer points to.
>>> First because of int *p = &s.i;  with struct { int i; ... } s; points
>>> to an int but it also points
>>> to the start of an aggregate (and so can be trivially casted to a
>>> pointer to s).  Second because
>>> GCCs middle-end (thus GIMPLE) ignores pointer types completely so you can
>>> have
>>> an SSA name a_1 of type int *X and a dereference a_1->b.c (thus a_1 points
>>> to a
>>> structure object even though it is of type int *).
>>>
>>
>> Thanks for this word of caution :)
>>
>> We understand your example (where SSA variable a_1 is of type int * and it
>> is dereferenced as a_1->b.c) with the following explanation: Since GIMPLE
>> based transformations ignore the type information completely, it could
>> differ flow sensitively for variables and is left implicit. In other words,
>> the type of a variable in an expression could differ from its type available
>> in VAR_DECL. For the above example, the type of a_1 in VAR_DECL is int *
>> whereas it is actually used as a pointer to a struct in the expression
>> a_1->b.c because of some code transformations.
>>
>> Fortunately, we do not need the flow sensitive type of a variable in every
>> expression.
>>
>> Our basic need is much simpler: We would like to know if a pointer is used
>> for iteratively accessing a recursive data structure (such as a list),  in a
>> loop or recursive invocation as illustrated below. Due to some
>> transformations, can a pointer to int show up for such accesses in GIMPLE or
>> would it always have RECORD_TYPE in its type expression for such limited
>> situations?
>>
>> while (...)
>> {
>>     x = x->f;
>>     ...
>> }
>>
>> At the source level, x is guaranteed to be a pointer to a struct. Our
>> question is: Does this guarantee hold in GIMPLE in the limited situations of
>> such iterative accesses to a recursive data structure?
>
> No, it doesn't.
>
>> In particular, if this guarantee does not hold for a sequential access
>> pattern such as below, it is a non-issue for us.
>>
>> x = x->f;
>> x = x->f;
>> x = x->f;
>
> struct X { struct X *f; };
> struct X *foo (void *p)
> {
>   p = ((struct X *)p)->f;
>   p = ((struct X *)p)->f;
>   p = ((struct X *)p)->f;
>   return p;
> }
>
> is represented as
>
> foo (void * p)
> {
>   <bb 2>:
>   p_3 = MEM[(struct X *)p_2(D)].f;
>   p_4 = MEM[(struct X *)p_3].f;
>   p_5 = MEM[(struct X *)p_4].f;
>   return p_5;
> }
>
> all pointer types are void *.  At accesses you have types of access of course,
> but the pointers themselves can have any pointer type (such as void * here
> or int * if you change the type of p).

Or

struct X { struct X *f; };
struct X *foo (void *p)
{
  struct X **q = &((struct X *)p)->f;
  p = *q;
  q = &((struct X *)p)->f;
  p = *q;
  q = &((struct X *)p)->f;
  p = *q;
  return p;
}

foo (void * p)
{
  struct X * * q;

  <bb 2>:
  p_4 = MEM[(struct X * *)p_1(D)];
  p_6 = MEM[(struct X * *)p_4];
  p_8 = MEM[(struct X * *)p_6];
  return p_8;
}

or if you make q void ** then

foo (void * p)
{
  void * * q;

  <bb 2>:
  p_4 = MEM[(void * *)p_1(D)];
  p_6 = MEM[(void * *)p_4];
  p_8 = MEM[(void * *)p_6];
  return p_8;
}

Richard.

> Richard.
>
>> What gives us a ray of hope is our hunch that the code transformations for
>> iterative accesses are far more limited than they are for sequential
>> accesses.
>>
>> Thanks and regards,
>>
>> Uday.
>>
>>
>>

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