On Sat, Nov 02, 2013 at 03:15:44PM +0000, Richard Sandiford wrote:
> What should integer_onep mean if we have a signed 1-bit bitfield in
> which the bit is set? Seen as a 1-bit value it's "obviously" 1,
> but seen as a value extended to infinite precision it's -1.
>
> Current mainline returns false while wide-int returns true.
Then current mainline is correct. signed 1-bit bitfield has values
0 and -1, not 0 and 1. And, signed 1-bit -1 should be just
integer_minus_onep and integer_all_onesp.
Jakub
