On 01/14/2013 08:34 AM, Mischa Baars wrote:
> When running the example attached, you can see the compiler fails to 
> recognize not-a-number's properly.
> 
> Anyone who would like to have a look?

Comparing NaN with anything always returns false.  Even when comparing
with NaN.

You want:

        if (x != x)
        {
                printf("found a not-a-number\n");
        }

Andrew.

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