On 10/11/2012 03:48 PM, Alexandre Oliva wrote:
This is not entirely clear to me; where is i defined in the first place?
Um, it's defined where the user writes the definition, like any other variable.
Is it i_init that defines and tests i_initialized?
Yes.
Consider instead the following expansion: __thread void (*i_initialize)(void) = i_init;
That would work too, though it wouldn't have the benefit of link-compatibility with __thread (for variables that don't need dynamic initialization) that the current scheme has.
I don't know whether it would be more or less efficient.
or this: [EXTERN] __thread T *i;
Same answer. If we aren't trying to maintain compatibility, this approach seems like it would be more efficient than i_initialize.
Jason
