On 20 April 2011 10:10, Boris Kolpackov wrote:
>
>> What about std::size_t?
>
> This one is actually covered. In GCC AST std::size_t node is the same
> as ::size_t (i.e., GCC does not create new *_TYPE node for using-
> declarations).
My point is that libstdc++ does not use a using declaration for
std::size_t, in c++config.h there is:
namespace std
{
typedef __SIZE_TYPE__ size_t;
This means std::size_t is a synonym for the same underlying type as
size_t, but in a separate tree.
>> That could be defined as a synonym for __SIZE_TYPE__ or decltype(sizeof(1))
>> so is not in a sequence of typedef declarations that includes size_t.
>
> If it were defined as one of these, I could then check for both ::size_t
> and ::std::size_t.
OK. Sorry I don't know the answer to your question.
