Hello Uday,
On Tue, Sep 14, 2010 at 11:50:11PM +0530, Uday P. Khedker wrote:
> [..]
> The point is: in your program is is only a pointer. When you pass s
> as a parameter to printf, the compiler assumes that only s is being
> used so the (effective) assignment
>
> *s = 'H'
>
> is deleted as dead code when optimization is enabled.
I can't believe your argumentation is correct. Wouldn't that mean:
When I have a code, where I only pass the pointer to a function like:
void f(int *);
int main(){
int *s = (int *)malloc(100,sizeof(int));
for(int i = 0; i < 100; ++i)
s[i] = 0;
f(s);
free(s);
}
The compiler would be allowed to erase the complete for-loop? And thus
the initialization of the array?
Or I did misunderstand your argumentation...
Axel
