Thank you very much!!! :D
--- Mer 24/3/10, Ian Lance Taylor <i...@google.com> ha scritto:
> Da: Ian Lance Taylor <i...@google.com>
> Oggetto: Re: Problem with ADDR_EXPR array offset
> A: "Massimo Nazaria" <ma...@rocketmail.com>
> Cc: gcc@gcc.gnu.org
> Data: Mercoledì 24 marzo 2010, 23:59
> Massimo Nazaria <ma...@rocketmail.com>
> writes:
>
> > I'm working on a pass and I need to handle some
> pointer expressions.
> > For example, I have this C-code:
> > int v[1000];
> > int *p;
> > p = &v[10];
> >
> > The problem is that, when I'm trying to parse "p =
> &v[10];", I'm not able to get the array offset (10 in
> this case).
> >
> > Namely, for a given statement like "p = &v[10]", I
> need to get:
> > array: v (I can do that)
> > offset: 10
> >
> > Here is the code I am working on:
> > op0 = gimple_op (stmt, 0);
> > op1 = gimple_op (stmt, 1);
> >
> > if (gimple_assign_rhs_code (stmt) ==
> ADDR_EXPR)
> > {
> > base = get_base_address
> (TREE_OPERAND (op1, 0)); // the array v, OK
> > offset = // ???
> >
> > How can I do?
>
> There is nothing wrong with calling get_base_address, but
> by doing
> that you have thrown away the offset information. I
> would expected
> TREE_OPERAND (op1, 0) to be an ARRAY_REF. Operand 0
> of that will be
> an array, operand 1 will be an index.
>
> I would recommend taking a look at get_inner_reference
> rather than
> get_base_address.
>
> Ian
>
