Tony Bernardin <sarus...@gmail.com> writes: > Hey, I'm having a little trouble understanding the conversion gcc is > doing in a statement with the following types:
This question is not appropriate for the mailing list gcc@gcc.gnu.org, which is for gcc developers. It would be appropriate for gcc-h...@gcc.gnu.org. Please take any followups to gcc-help. Thanks. > int64 = int32 * uint32 According to the rules of the C++ language, this will convert the int32 to uint32, do a uint32 multiplication producing a uint32 result, and then zero extend the uint32 result to assign it to int64. This seems consistent with the output you reported. Ian
