Florian Weimer <f...@deneb.enyo.de> writes:
> * Joshua Haberman:
>
>> To me this allows the following:
>>
>> int i;
>> union u { int x; } *pu = (union u*)&i;
>> printf("%d\n", pu->x);
>
> I think the cast on the secodn line is undefined,
Only if union u has stricter alignment requirements than int; otherwise
you are guaranteed to get back the original pointer when casting back to
int*.
Andreas.
--
Andreas Schwab, sch...@linux-m68k.org
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"And now for something completely different."
