On Sat, Nov 28, 2009 at 5:31 PM, Tim Prince <n...@aol.com> wrote:
> Richard Guenther wrote:
>>
>> On Sat, Nov 28, 2009 at 4:26 PM, Tim Prince <n...@aol.com> wrote:
>>>
>>> Toon Moene wrote:
>>>>
>>>> H.J. Lu wrote:
>>>>>
>>>>> On Sat, Nov 28, 2009 at 3:21 AM, Toon Moene <t...@moene.org> wrote:
>>>>>>
>>>>>> L.S.,
>>>>>>
>>>>>> Due to the discussion on register allocation, I went back to a hobby
>>>>>> of
>>>>>> mine: Studying the assembly output of the compiler.
>>>>>>
>>>>>> For this Fortran subroutine (note: unless otherwise told to the
>>>>>> Fortran
>>>>>> front end, reals are 32 bit floating point numbers):
>>>>>>
>>>>>> subroutine sum(a, b, c, n)
>>>>>> integer i, n
>>>>>> real a(n), b(n), c(n)
>>>>>> do i = 1, n
>>>>>> c(i) = a(i) + b(i)
>>>>>> enddo
>>>>>> end
>>>>>>
>>>>>> with -O3 -S (GCC: (GNU) 4.5.0 20091123), I get this (vectorized) loop:
>>>>>>
>>>>>> xorps %xmm2, %xmm2
>>>>>> ....
>>>>>> .L6:
>>>>>> movaps %xmm2, %xmm0
>>>>>> movaps %xmm2, %xmm1
>>>>>> movlps (%r9,%rax), %xmm0
>>>>>> movlps (%r8,%rax), %xmm1
>>>>>> movhps 8(%r9,%rax), %xmm0
>>>>>> movhps 8(%r8,%rax), %xmm1
>>>>>> incl %ecx
>>>>>> addps %xmm1, %xmm0
>>>>>> movaps %xmm0, 0(%rbp,%rax)
>>>>>> addq $16, %rax
>>>>>> cmpl %ebx, %ecx
>>>>>> jb .L6
>>>>>>
>>>>>> I'm not a master of x86_64 assembly, but this strongly looks like
>>>>>> %xmm{0,1}
>>>>>> have to be zero'd (%xmm2 is set to zero by xor'ing it with itself),
>>>>>> before
>>>>>> they are completely filled with the mov{l,h}ps instructions ?
>>>>>>
>>>>> I think it is used to avoid partial SSE register stall.
>>>>>
>>>>>
>>>> You mean there's no movaps (%r9,%rax), %xmm0 (and mutatis mutandis for
>>>> %xmm1) instruction (to copy 4*32 bits to the register) ?
>>>>
>>> If you want those, you must request them with -mtune=barcelona.
>>
>> Which would then get you movups (%r9,%rax), %xmm0 (unaligned move).
>> generic tuning prefers the split moves, AMD Fam10 and above handle
>> unaligned moves just fine.
>
> Correct, the movaps would have been used if alignment were recognized.
> The newer CPUs achieve full performance with movups.
> Do you consider Core i7/Nehalem as included in "AMD Fam10 and above?"
I'd have to consult the optimization manual of those, but HJ may know
off-head.
Richard.
