On Mon, 8 Jun 2009, Kaveh R. GHAZI wrote: > If I write a complex double constant -3.I (as opposed to 0-3.I), what is > it supposed to evaluate to? This program:
Because GCC does not implement imaginary types, this applies unary minus to 0.0+3.0I. Whereas 0-3.I means 0.0 - (0.0+3.0I), a mixed real/complex operation, the real part of whose result is 0.0 except when rounding towards negative infinity when it is -0.0. There are lots of tests in gcc.dg/torture/complex-sign*. -- Joseph S. Myers jos...@codesourcery.com
