Paolo Carlini wrote:
> Neal Becker wrote:
>> gcc-4.3.0-8.x86_64
>>
>> I have test code that does passes std::isfinite (x), yet if I print the
>> values to std::cout the value printed is 'inf'. Is std::isfinite (x)
>> broken?
>>
> Whatever bug it may have - it can, of course - std::isfinite returns an
> *int*, therefore your statement seems at the very least rather weird. A
> self-contained testcase is badly needed.
>
> Paolo.
I found that compiling without -ffast-math would allow std::isfinite to
work. Sorry if the statement was confusing. The code looks something
like:
[calculate x]
if (not isfinite (x))
throw std::runtime_error ("blah")
