On Mon, May 12, 2008 at 6:54 PM, Richard Kenner <[EMAIL PROTECTED]> wrote: >> I gues you'll get funny effects then, as for Nbit sizetype there's >> usually no valid mode for (N+8)bit bitsizetype. In fact, I believe >> bitsizetype simply "inherits" the mode from sizetype. > > No. We pick the mode that's *at least* 3 bits wider than sizetype, so > it's usually the next larger integer mode. >
Does this mean that if the sizetype is 32bit then bitsizetype is 64bit? Regards, Shafi
