Herman Geza <[EMAIL PROTECTED]> writes: [...]
> What is the correct way to do this:
>
> void setNaN(float &v) {
> reinterpret_cast<int&>(v) = 0x7f800001;
> }
>
> without a type-prunning warning? I cannot use the union trick here
Why? Won't the following work?
void setNaN(float &v) {
union { float f; int i; } t;
t.i = 0x7f800001;
v = t.f;
}
-- Sergei.
