---------- Forwarded message ---------- From: Igor Bukanov <[EMAIL PROTECTED]> Date: Oct 31, 2006 9:48 PM Subject: Re: return void from void function is allowed. To: Mike Stump <[EMAIL PROTECTED]>
On 10/31/06, Mike Stump <[EMAIL PROTECTED]> wrote:
This is valid in C++.
My copy of 1997 C++ public draft contains: 6.6.3 The return statement ... 2 A return statement without an expression can be used only in functions that do not return a value, that is, a function with the return value type void, a constructor (_class.ctor_), or a destructor (_class.dtor_). A return statement with an expression can be used only in functions returning a value; the value of the expression is returned to the caller of the function. If required, the expression is implicitly converted to the return type of the function in which it appears. A return statement can involve the construction and copy of a temporary object (_class.temporary_). Flowing off the end of a function is equivalent to a return with no value; this results in undefined behavior in a value-returning function. My reading of that is C++ does not allow return void-expression from void function. Was it changed later?
And final thought, wrong mailing list... gcc-help would have been
better. I thought bugs in GCC can be discussed here. Sorry if it is a wrong assumption. Regards, Igor
