On Mar 6, 2006, at 5:21 AM, Pierre Chatelier wrote:
This is ok to fix the source, but I do not understand why it is normal behaviour that the foo() in b hides the one from a. They have different prototypes.
That's just how C++ is designed/defined, any book on C++ should be able to explain this in more detail. Basically, a designer of a class is expected to think about each overload and decide if they want members from bases classes or not and which ones they want in the overload set. Trying to abdicate this means they just want the ones the explicitly defined in the class to be seen and no others.
