Consider the following short program:
#include <algorithm>
void Tst1(short* __restrict__ SrcP, short* __restrict__ MinP, int Len)
{
for (int x=0; x<Len; x++)
MinP[x] = SrcP[x] <? MinP[x];
}
void Tst2(short* __restrict__ SrcP, short* __restrict__ MinP, int Len)
{
for (int x=0; x<Len; x++)
MinP[x] = std::min(SrcP[x], MinP[x]);
}
If I compile it with
gcc41 -O2 -ftree-vectorize -ftree-vectorizer-verbose=5
function Tst1 gets vectorized but Tst2 not.
The reason for this is <? results in a MIN_EXPR while std::min generates a
conditional code.
My question is, how can I get a MIN_EXPR without using the deprecated min <?
operator?
Michael Cieslinski
