On Tue, Nov 08, 2022 at 03:06:53PM +0100, Aldy Hernandez wrote:
> +// If either operand is a NAN, set R to the combination of both NANs
> +// signwise and return TRUE.

This comment doesn't describe what it does now.
If either operand is a NAN, set R to NAN with unspecified sign bit and return
TRUE.
?

Other than this LGTM.

        Jakub

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