On Tue, Nov 08, 2022 at 02:47:35PM +0100, Aldy Hernandez wrote:
> Well, perhaps we should just nuke update_nan_sign() altogether, and
> always keep the sign varying?
>
> inline bool
> propagate_nans (frange &r, const frange &op1, const frange &op2)
> {
> if (op1.known_isnan () || op2.known_isnan ())
> {
> r.set_nan (op1.type ());
> return true;
> }
> return false;
> }
>
> I'm fine either way. The less code the better :).
Yes, but you had 2 callers, so something needs to be done also if
in foperator_plus::fold_range.
Jakub
