In C++14 a constexpr function doesn't need to return a value.
Tested x86_64-pc-linux-gnu, applying to trunk.
commit 9675a7bde41b5430197854d8c1822c8f4d95b95e Author: Jason Merrill <ja...@redhat.com> Date: Fri Jan 9 01:46:16 2015 -0500 PR c++/64547 * constexpr.c (cxx_eval_call_expression): A call to a void function doesn't need to return a value. diff --git a/gcc/cp/constexpr.c b/gcc/cp/constexpr.c index 9a0d518..650250b 100644 --- a/gcc/cp/constexpr.c +++ b/gcc/cp/constexpr.c @@ -1386,6 +1386,8 @@ cxx_eval_call_expression (const constexpr_ctx *ctx, tree t, value by evaluating *this, but we don't bother; there's no need to put such a call in the hash table. */ result = lval ? ctx->object : ctx->ctor; + else if (VOID_TYPE_P (TREE_TYPE (res))) + result = void_node; else { result = *ctx->values->get (slot ? slot : res); diff --git a/gcc/testsuite/g++.dg/cpp1y/constexpr-void2.C b/gcc/testsuite/g++.dg/cpp1y/constexpr-void2.C new file mode 100644 index 0000000..321a35e --- /dev/null +++ b/gcc/testsuite/g++.dg/cpp1y/constexpr-void2.C @@ -0,0 +1,21 @@ +// PR c++/64547 +// { dg-do compile { target c++14 } } + +struct X +{ + int x; + constexpr int get() const {return x;} + constexpr void set(int foo) {x = foo;} +}; + +constexpr int bar() +{ + X x{42}; + x.set(666); + return x.get(); +} + +int main() +{ + constexpr int foo = bar(); +}