https://gcc.gnu.org/bugzilla/show_bug.cgi?id=102084
Andrew Pinski <pinskia at gcc dot gnu.org> changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution|--- |INVALID
--- Comment #3 from Andrew Pinski <pinskia at gcc dot gnu.org> ---
Your code is the same as this code:
template <typename T>
std::function<const T&()> constant_ref_broken(const T& c) {
return [c]() noexcept -> const T { return c; };
}
So you are returning a non-reference and then have a return of a refence.
Nothing shocking.
If you want to capture the reference of c and return the reference rather than
what points to the refence you need c++14 to do that and this code works and
does what you originally wanted:
template <typename T>
std::function<const T&()> constant_ref_broken(const T& c) {
return [&c]() noexcept -> decltype(auto) { return c; };
}
