On Fri, Aug 9, 2013 at 9:34 AM, Fleuriot Damien <m...@my.gd> wrote:
>
> On Aug 8, 2013, at 10:27 AM, Peter Wemm <pe...@wemm.org> wrote:
>
>> On Thu, Aug 8, 2013 at 12:04 AM, s m <sam.gh1...@gmail.com> wrote:
>>> hello guys,
>>>
>>> i have a question about ip addresses. i know my question is not related to
>>> freebsd but i googled a lot and found nothing useful and don't know where i
>>> should ask my question.
>>>
>>> i want to know how can i calculate the number of ip addresses in a range?
>>> for example if i have 192.0.0.1 192.100.255.254 with mask 8, how many ip
>>> addresses are available in this range? is there any formula to calculate
>>> the number of ip addresses for any range?
>>>
>>> i'm confusing about it. please help me to clear my mind.
>>> thanks in advance,
>>
>> My immediate reaction is.. is this a homework / classwork / assignment?
>>
>> Anyway, you can think of it by converting your start and end addresses
>> to an integer. Over simplified:
>>
>> $ cat homework.c
>> main()
>> {
>> int start = (192 << 24) | (0 << 16) | (0 << 8) | 1;
>> int end = (192 << 24) | (100 << 16) | (255 << 8) | 254;
>> printf("start %d end %d range %d\n", start, end, (end - start) + 1);
>> }
>> $ ./homework
>> start -1073741823 end -1067122690 range 6619134
>>
>> The +1 is correcting for base zero. 192.0.0.1 - 192.0.0.2 is two
>> usable addresses.
>>
>> I'm not sure what you want to do with the mask of 8.
>>
>> You can also do it with ntohl(inet_addr("address")) as well and a
>> multitude of other ways.
>
>
> Hold on a second, why would you correct the base zero ?
> It can be a valid IP address.
There is one usable address in a range of 10.0.0.1 - 10.0.0.1.
Converting to an integer and subtracting would be zero. Hence +1.
--
Peter Wemm - pe...@wemm.org; pe...@freebsd.org; pe...@yahoo-inc.com; KI6FJV
UTF-8: for when a ' just won\342\200\231t do.
<brueffer> ZFS must be the bacon of file systems. "everything's better with ZFS"
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