* Stephen Montgomery-Smith <[EMAIL PROTECTED]> [020104 12:02] wrote:
> I want to create a Makefile for a C program that includes some Pentium
> II specific inline assembler code. How do I tell the compiler whether
> we are compiling on a i686?
>
> For Linux, I can do something like this (for gnu-make)
> Arch = $(shell arch)
> cc ...... -DArch .....
>
> and inside the program
>
> #ifdef i686
>
> But arch doesn't exist on FreeBSD.
Isn't this somewhat trivial?
ARCH=i686
CFLAGS+=-D${ARCH}
?
--
-Alfred Perlstein [[EMAIL PROTECTED]]
'Instead of asking why a piece of software is using "1970s technology,"
start asking why software is ignoring 30 years of accumulated wisdom.'
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