I want to create a Makefile for a C program that includes some Pentium II specific inline assembler code. How do I tell the compiler whether we are compiling on a i686?
For Linux, I can do something like this (for gnu-make) Arch = $(shell arch) cc ...... -DArch ..... and inside the program #ifdef i686 But arch doesn't exist on FreeBSD. -- Stephen Montgomery-Smith [EMAIL PROTECTED] http://www.math.missouri.edu/~stephen To Unsubscribe: send mail to [EMAIL PROTECTED] with "unsubscribe freebsd-hackers" in the body of the message
