Re: rfork() [was: Concept check]

[Wes Peters]

Matthew Dillon wrote:
> 
> :>
> :>     The reason is that rfork(RFMEM) does not give the new process a new
> :>     stack, so both the old and new processes wind up on the same original
> :>     stack and stomp all over each other.
> :
> :There is an implementation of clone() in the linuxthreads port, written by
> :Richard Seaman.
> :
> :Jason
> 
>     No manual page, tho :-(

Sheldon, do you want to tackle that one?  You seem to be in a manpage mood
these days.

-- 
            "Where am I, and what am I doing in this handbasket?"

Wes Peters                                                         Softweyr LLC
[EMAIL PROTECTED]                                           http://softweyr.com/


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