Re: rfork() [was: Concept check]

[Matthew Dillon]

:> 
:>     The reason is that rfork(RFMEM) does not give the new process a new
:>     stack, so both the old and new processes wind up on the same original
:>     stack and stomp all over each other.
:
:There is an implementation of clone() in the linuxthreads port, written by
:Richard Seaman.
:
:Jason

    No manual page, tho :-(

                                        -Matt
                                        Matthew Dillon 
                                        <[EMAIL PROTECTED]>


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