On Wednesday, April 10, 2013 2:28:38 am Lev Serebryakov wrote: > Hello, John. > You wrote 10 апреля 2013 г., 0:58:22: > > >> Problem is, that every uart device now is independent from each > >> other in good "OOP" style, and it looks like interrupt sharing we > >> need one interrupt handler per irq (not per device), which will now > >> about several UARTs. Something like "multiport" device, bot not > >> exactly. > JB> No, the interrupt code itself will handle shared interrupts (it will > JB> call all handlers). I think in practice that uart is setting > And what will happen, if there is two UARTs asserting interrupt in > same time? First one returns "FILTER_HANDLED", will second handler be > called?
They are all called in turn. > ISA interrupt sharing IS NOT so simple. sio contains a lot of > obscure code to work. INTR_FAST handlers in 4.x didn't use to allow sharing. That changed in 6.x or so. > JB> INTR_EXCL or some such and/or uart doesn't set RF_SHAREABLE when > JB> allocating the IRQ. It is probably the latter. You could try just > JB> adding RF_SHAREABLE to the bus_alloc_resource_any() for the IRQ to > JB> uart and see if that fixes it. > sc->sc_ires = bus_alloc_resource_any(dev, SYS_RES_IRQ, &sc->sc_irid, > RF_ACTIVE | RF_SHAREABLE); > > It is here. Ok, then you need to figure out what is actually failing to install an interrupt handler (e.g. does bus_alloc_resource or bus_setup_intr fail?) -- John Baldwin _______________________________________________ freebsd-current@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-current To unsubscribe, send any mail to "freebsd-current-unsubscr...@freebsd.org"
