On 9 April 2013 23:28, Lev Serebryakov <l...@freebsd.org> wrote: > Hello, John. > You wrote 10 апреля 2013 г., 0:58:22: > >>> Problem is, that every uart device now is independent from each >>> other in good "OOP" style, and it looks like interrupt sharing we >>> need one interrupt handler per irq (not per device), which will now >>> about several UARTs. Something like "multiport" device, bot not >>> exactly. > JB> No, the interrupt code itself will handle shared interrupts (it will > JB> call all handlers). I think in practice that uart is setting > And what will happen, if there is two UARTs asserting interrupt in > same time? First one returns "FILTER_HANDLED", will second handler be > called? > > ISA interrupt sharing IS NOT so simple. sio contains a lot of > obscure code to work.
.. surely it's solvable with a bit of ugliness? Eg, looping over them until they all return "not handled" or you hit a limit, or something equally ew. .. assuming that it is broken in the first place, that is. Adrian _______________________________________________ freebsd-current@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-current To unsubscribe, send any mail to "freebsd-current-unsubscr...@freebsd.org"
