> On Dec 2, 2018, at 8:11 PM, Sven Barth via fpc-pascal
> <fpc-pascal@lists.freepascal.org> wrote:
>
> Also the idea should be that a non-generic routine takes precedence.
>
I did this wrong then because the generic takes precedence now. Why shouldn’t
the generic take precedence though? It comes after so you think it would hide
the first one. The symbol “DoThis” is now a generic dummy (compiler term) so I
didn’t know you could even get access to the first DoThis.
procedure DoThis(msg:integer);
begin
writeln('DoThis:',msg);
end;
generic procedure DoThis<T>(msg:T);
begin
writeln('DoThis$1:',msg);
end;
begin
DoThis(1); // DoThis$1:1
end.
Regards,
Ryan Joseph
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