Dear Paul, hope you have got change to go through the attached files.
---Emam On Monday, February 6, 2017 at 10:01:43 AM UTC+5:30, Emamuddin Shah wrote: > > Hi Paul, > > Hope you have received my email. > > Regards > Emam > > On Wednesday, February 1, 2017 at 12:52:28 PM UTC+5:30, Emamuddin Shah > wrote: >> >> Dear Paul, >> >> i will share my both excel sheets, so that you can check where iam wrong >> and correct it, since the document is confidential i cant share here, plz >> provide your email id. >> >> regards >> Emam >> >> On Thursday, October 20, 2016 at 7:04:17 PM UTC+5:30, Paul Schreiner >> wrote: >>> >>> Mr. Emamuddin, >>> >>> I'm looking through your code and have encountered some issues. >>> >>> First, your sample file is only one sheet, >>> with a Header in row 1 and 2 rows of data in 24 columns (A:X) >>> >>> In your code, you use: >>> >>> sc = Sheets.Count >>> Which, of course sets the variable "sc" equal to the total number of >>> sheets. >>> >>> but, when you use: >>> For c = 1 To 27 >>> cold(c) = Sheets(sc).Cells(c, 3).Value >>> Next c >>> >>> You're loading data from the LAST sheet of the workbook. >>> Using your sample file, having only 1 sheet, this will use this sheet. >>> However, your variables "c" and "cold" IMPLY "column" and "Column-Old" >>> >>> but your in your loop: the Cells() function syntax is "Cells(row,column) >>> which means that your loop is loading ROWS 1 to 27, column 3 (C) into >>> the cold() array. >>> >>> Your next loop: >>> For b = lr - (size - 1) To lr >>> >>> will fail with your sample file, since: >>> lr = 4 >>> size = 100 >>> >>> so your loop is: >>> For b = -95 to 4 >>> >>> In the first iteration, it will fail for row -95 of the cells() function. >>> >>> Of course, I cannot test the code: >>> Workbooks.Open Filename:=Sheets(sc).Cells(1, 8), >>> Password:=Sheets(sc).Cells(10, 8).Value >>> >>> because the sample file does not have a filename in row 1, column "H" >>> >>> I suggest you utilize the "breakpoint" functionality of the VBEditor and >>> step through your program one line at a time and monitor the variables. >>> >>> also, to help you with reading the code, try using the column LETTER in >>> the cells() function when you can. >>> >>> That is: Cells(1,"C") for row 1, column C instead of cells(1,3) >>> You're less likely to confuse the row/column. >>> >>> Of course, this doesn't apply when you're referring to the array index. >>> >>> *Paul* >>> ----------------------------------------- >>> >>> >>> >>> >>> >>> >>> >>> *“Do all the good you can,By all the means you can,In all the ways you >>> can,In all the places you can,At all the times you can,To all the people >>> you can,As long as ever you can.” - John Wesley* >>> ----------------------------------------- >>> >>> >>> On Wednesday, October 19, 2016 7:39 AM, Emamuddin Shah <emt...@gmail.com> >>> wrote: >>> >>> >>> there are x rows more than 100 in that i want to update 50 rows or 20 >>> rows whatever. >>> iam able to get row details in array, but those details are not getting >>> updated on next workbook >>> >>> i have attached exscel sheet format which iam using, there is 1 more >>> similar file with coloumns shuffeled >>> please find attached >>> >>> On Tuesday, October 18, 2016 at 7:11:00 PM UTC+5:30, Paul Schreiner >>> wrote: >>> >>> I'm trying to follow. >>> There are easier ways to load the array from the cell values, but I'll >>> get to that later. >>> >>> But: >>> You said that you have 50 rows. >>> that means that with: >>> lr = Activecell.Cells(.Rows.count, "A").End(xlUp).Row + 1 >>> >>> lr (last row) = 51 >>> you set: >>> size = 100 >>> So, for your loop: >>> For b = lr - (size - 1) To lr >>> >>> b = 51 -(100-1) to 51 >>> or >>> b = -48 to 51 >>> >>> so this should produce an error when you execute: >>> >>> cmail(ab) = Cells(b, cold(7)).Value >>> >>> What are the values in column "C" rows 1-27? >>> from your use of cold(), they must be integers. >>> >>> Can you send me a sample file? >>> we can step through it and figure out what happens in the second >>> iteration. >>> >>> *Paul* >>> ------------------------------ ----------- >>> >>> >>> >>> >>> >>> >>> >>> *“Do all the good you can,By all the means you can,In all the ways you >>> can,In all the places you can,At all the times you can,To all the people >>> you can,As long as ever you can.” - John >>> Wesley*------------------------------ >>> ----------- >>> >>> >>> On Tuesday, October 18, 2016 8:49 AM, Emamuddin Shah <emt...@gmail.com> >>> wrote: >>> >>> >>> ITS NOT UPDATED ALL 50 STRINGS ROW DETAILS. >>> IT IS UPDATING ONLY FIRST MATCHED STRING ROW. >>> >>> On Tuesday, October 18, 2016 at 6:13:56 PM UTC+5:30, Emamuddin Shah >>> wrote: >>> >>> Hello >>> >>> Iam trying to Loop so that it matched a string and then fills cells in >>> that row. >>> say i have 50 strings to be matched and then update date on that row, >>> data i have stored in ARRAY >>> >>> here is my part of code where I am struck >>> >>> >>> ++++++++++++++++++= >>> cm = 1 >>> >>> For i = 2 To lri >>> >>> >>> If Cells(i, 7) = cmail(cm) Then >>> Cells(i, 15).Value = stat1(cm) >>> Cells(i, 16).Value = stat2(cm) >>> Cells(i, 17).Value = ccdate(cm) >>> Cells(i, 18).Value = ctime(cm) >>> cm = cm + 1 >>> End If >>> >>> Next >>> ++++++++++++++++++++++++++++++ + >>> >>> -- >>> Are you =EXP(E:RT) or =NOT(EXP(E:RT)) in Excel? 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