On Monday, January 20, 2025 at 2:13:21 PM UTC-7 Jesse Mazer wrote:

On Mon, Jan 20, 2025 at 3:30 PM Alan Grayson <agrays...@gmail.com> wrote:

Below is what Brent wrote to describe his plots: notice that he uses the 
car moving at 0.8c. But respect to what? He doesn't say.


I would actually quibble with his statement "In both diagrams the car is 
moving to the right at 0.8c", since in the diagram for the car's frame the 
car isn't moving at all, but I'm sure if asked to clarify he'd say he just 
meant that both diagrams show a scenario where the car has a velocity of 
0.8c relative to the garage, so this doesn't actually lead me to be 
confused about his scenario the way some of your statements do (in part 
because you refuse to give a straightforward numerical example like Brent 
did). And everything else in his quote does clearly specify whether he is 
talking about what's true in "the car's reference frame" or in "the 
garage's reference frame" (naming the frame of a specific object as I have 
asked you to do), he uses variations of those phrases several times.

 

And then he contracts the car from the garage frame. Is garage frame moving 
or at rest? He doesn't say. So much presumably ambiguous non standard 
terminology and not a peep out of you. 


Here you seem confused about what I am saying is "non standard 
terminology"--I think it's GOOD that Brent doesn't declare one frame to be 
"moving" and the other to be "at rest", because that is precisely the sort 
of confusing non-standard terminology YOU use that I'm objecting to! In the 
standard terminology, one wouldn't say a given frame is "at rest" or 
"moving" except as part of a longer phrase that specifies some other object 
or frame those words are supposed to be relative to, like "the car is 
moving relative to the garage frame" or "the garage is moving relative to 
the car frame" or "the car is at rest relative to the car frame", with 
these phrases just telling you something about the velocity of the named 
object in the named frame.

 

Let's do this; since this discussion has reached the point of tedious 
worthlessness, let's terminate it. AG


As I said, one easy way to avoid terminological confusion would be to 
answer my simple request for a numerical example: "give me a specific 
number for the rod's speed in the Earth's inertial rest frame, its 
direction (in the +x or -x direction), and the initial position of each end 
of the rod at t=0 in the Earth frame". 

Is there some reason you are unwilling to give me a few numbers for 
velocity and initial position of the rod in the Earth frame to work with? 
If you did, I could then show you with a little simple algebra what happens 
when we use the LT to transform these numbers into the rod's frame, proving 
that when we do this the length of the rod is predicted to be EXPANDED 
rather than contracted, compared to its length in the Earth frame.


*Yes, two reasons. Firstly, you can use Brent's numbers which he uses in 
his plots; and secondly, it seems as if your results contradict length 
contraction, so they are suspect. As for standard terminology, since motion 
is relative, what's wrong with saying the rod is moving relative to the 
Earth, towad the Earth, at some speed v, so the Earth can be imagined as at 
rest? AG *


Jesse
 


"First note by comparing the two diagrams that the car is longer than the 
garage, 12' vs 10'.  So the car doesn't fit at small relative speed.  What 
does "fit" mean?  It means that the event of the front of the car 
coinciding with the right-hand end of the garage is after or at the same 
time as the rear of the car coinciding with the left-had end of the 
garage.  In both diagrams the car is moving to the right at 0.8c so 
\gamma=sqrt{1-0.8^2}=0.6.  Consequently, in the car's reference frame, the 
garage is contracted to 6' length and when the rear of the car is just 
entering the garage, the front is *simultaneously*, in the car's reference 
frame, already 6' beyond the right-hand end of the garage.  Then in the 
garage's reference frame the car's length is contracted to 0.6*12'=7.2' so 
at the moment the front of the car coincides with the right end of the 
garage, the rear of the car will simultaneously, in the garage reference 
system, be 2.8' inside the garage as shown below."

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