On Wed, Feb 5, 2014 at 1:33 PM, Edgar L. Owen <[email protected]> wrote:
> Forget stops. > OK, if they're still moving fast relative to each other then each will see the others clock running slow. > Just assume A at the point just before he stops and is still > decellerating at 1g TO stop. The situation is exactly the same except for a > few nanoseconds. > No it is not. If A is decelerating then there has been a change in A's acceleration, the direction has changed as much as it's possible for it to change, by 180 degrees. The situation is no longer symmetrical and so what they see is not symmetrical, A sees B's clock running fast but B sees A's clock running slow, they age at different rates too. Of course if A is only decelerating slightly then B's clock will only seem to be running slightly fast, but then again if he's only decelerating slightly it will take a long time (ship time) to come to a stop, so when he does finally come to a stop A will find the discrepancy between his clock and his twin brother's clock to be large. > You've got the basic relativity wrong here. > Then Einstein got it wrong too. John K Clark -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/groups/opt_out.
