John, No, not at all.
Forget stops. Just assume A at the point just before he stops and is still decellerating at 1g TO stop. The situation is exactly the same except for a few nanoseconds. Also the apparent slowing of both A and B's clocks relative to each other is due to their relative velocities which is the same for each other and maxes at midpoint and by the time A arrives has SLOWLY dropped to zero. There simply is NO "springing forward thousands of years". That relative slowing is different than the ACTUAL slowing at the end of the journey. The relative slowing is NOT agreed upon. The actual slowing is. You've got the basic relativity wrong here. You need to correct that, then come back to my question of why the difference between relative and actual slowing... Edgar On Wednesday, February 5, 2014 12:25:11 PM UTC-5, John Clark wrote: > > On Wed, Feb 5, 2014 at 11:02 AM, Edgar L. Owen <[email protected]<javascript:> > > wrote: > > > both A and B experience the exact same 1g acceleration for the entire >> trip. >> > > Not if A comes to his destination AND STOPS. > > > A's watch doesn't suddenly spring back thousands of year in the second >> he finally cuts off his acceleration. >> > > True, but if A decelerated so quickly he came to a complete stop relative > to Earth in just one second then A will observe (assuming he has somehow > avoided being turned into a very very hot plasma, don't ask me how) that > B's watch springs FORWARD thousands of years in that one second. > > > Both A and B will each see each other's clock slowing >> > > Yes. > > > but when A reaches his destination only his clock will ACTUALLY be >> slowed, >> > > Only if A comes to a stop, and that can only happen is A starts to > accelerate in the opposite direction. If A does not stop then both will > continue to see each others clock as running slow. > > > and both A and B will agree on that. >> > > If A comes to a stop then both A and B will agree that their experiences > were NOT symmetrical, and both would agree that the readings on their > watches were not the same. > > John K Clark > > > > > > > > >> AND the accelerations of both A and B are both exactly equal 1g during >> the entire trip. >> >> So why is that? >> >> Edgar >> >> >> >> On Tuesday, February 4, 2014 1:02:52 PM UTC-5, John Clark wrote: >>> >>> On Mon, Feb 3, 2014 at 3:29 PM, Edgar L. Owen <[email protected]> wrote >>> >>> >>> > The question is why when A gets to the center of the galaxy and stops >>>> >>> >>> That's the key point to remember, A comes to a stop. And during the >>> deceleration process things would no longer be symmetrical, A would see B's >>> clock running Fast but B would see A's clock running slow. So A would have >>> aged less than B. >>> >>> > relative to B that then his clock shows only 20 years passage, but B's >>>> clock shows 30,000+? >>>> >>> >>> Actually if you work out the numbers you find that if A accelerated at >>> one g for 20 years ship time he'd only be 137 light years from Earth. After >>> 40 years ship time A would be 17,600 light years from Earth, and after 60 >>> years ship time A would be 2,480,000 light years from Earth and be at the >>> Andromeda Galaxy, although we on the Earth would have to wait 5 million >>> years to see A's ship get to Andromeda, and unfortunately he'd be going >>> much too fast to stop and sightsee. >>> >>> >>>> > Perhaps you didn't see my similar questions to Brent, to which he has >>>> either been unwilling or unable to reply, about this case. He says it's a >>>> matter of geometry, but neglects to point out that geometry must have its >>>> origin at B's earth bound frame. >>>> >>> >>> You can pick any point of origin and you will get the same answer, but >>> it's wise to pick an origin that makes the mathematics the easiest. >>> >>> John K Clark >>> >>> >>> >>> >>> >>> -- >> You received this message because you are subscribed to the Google Groups >> "Everything List" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to [email protected] <javascript:>. >> To post to this group, send email to [email protected]<javascript:> >> . >> Visit this group at http://groups.google.com/group/everything-list. >> For more options, visit https://groups.google.com/groups/opt_out. >> > > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/groups/opt_out.
