On 10/1/2025 7:13 PM, Alan Grayson wrote:


On Wednesday, October 1, 2025 at 6:11:55 PM UTC-6 Brent Meeker wrote:



    On 10/1/2025 6:38 AM, Alan Grayson wrote:


    On Wednesday, October 1, 2025 at 7:20:13 AM UTC-6 John Clark wrote:

        On Wed, Oct 1, 2025 at 8:29 AM Alan Grayson
        <[email protected]> wrote:

            /> Have physicists in the last 120 years claimed that two
            paths of different lengths in spacetime which start and
            end at same events, have the same accelerations, except
            Brent in his diagram? AG/


        *In a word, yes. Two worldlines between the same events in
        spacetime can have different lengths even if both involve
        acceleration. And proper time is the length of your world
        line. But of course if they have identical acceleration
        histories then they are in the same worldline, not a
        different one.*


    You're writing nonsense. Brent has two worldlines with different
    lengths, claiming they have identical accelerations. AG
    And he included diagrams showing the accelerations had the same
    amplitudes and durations.  And that even was redundant.  From the
    diagram it is clear that Red and Blue had the same velocity at the
    initiation of their accelerations and they turned their velocity
    thru the same angle in each period of acceleration...hence one can
    infer mathematically that their (acceleration*duration) products
    were the same.

    Brent


*That was your intention, but since the clock moving along the longer path, needs a greater turn if done in one acceleration, I don't think splitting the accelerations into two components solves your intention to make the accelerations of both paths equal. *
What the hell does "solves you intention" mean.  The velocities are the same and the angle thru which they turn is the same...those are hypotheticals of the story.  It follows that the (acceleration*duration) are the same.

*Recall that in the usual interpretation of the TP, where one twin is stationary and the other traveling, this situation is a limiting case of what you're doing in the diagram. *
NO, IT IS THE SAME CASE.  In my diagram it is clear that Blue is stationary for the duration of Red's trip.  Are you going to claim that it matters whether Blue was stationary some other time??

*It tends to confirm that the accelerations are not identical in your more general case. The only real proof of your claim is mathematically. The fact that your diagram affirms your claim is, IMO, insufficient. AG*
Which only shows how ignorant or unserious you are.

Brent

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