Bruce, The measure isn’t something I’m inventing, it’s implicit in the squared amplitudes of the wavefunction. The Schrödinger equation preserves the L² norm, and decoherence ensures that branches with extremely low amplitudes contribute negligibly to observer statistics. Ignoring that structure and treating all branches as equally weighted is not quantum mechanics, it’s just branch counting under a flat prior.
Quentin All those moments will be lost in time, like tears in rain. (Roy Batty/Rutger Hauer) Le mar. 26 août 2025, 08:29, Bruce Kellett <[email protected]> a écrit : > On Tue, Aug 26, 2025 at 4:21 PM Quentin Anciaux <[email protected]> > wrote: > >> You’re conflating mathematical possibilities with experiential >> frequencies. Yes, all 2^N sequences exist in the wavefunction, but their >> measures are not equal. The Born rule emerges because observers are not >> uniformly distributed across these sequences: almost all self-locating >> observers end up in high-measure branches. If you assume equal weighting, >> you’re rejecting the very structure of the wavefunction and replacing >> quantum mechanics with branch counting. >> > > I do not assume equal weighting. This argument has been tried before and > still fails because all 2^N sequences necessarily exist when every > possibility is realized on every trial. There is no probability associated > with the sequences, and all have equal weight simply by construction. The > "measure" you talk about is your own fantasy -- there is no unequal > "measure" between the sequences. You cannot give any reasonable account of > any such "measure" -- it does not follow from the Schroedinger equation or > any other postulate of quantum mechanics. > > Bruce > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion visit > https://groups.google.com/d/msgid/everything-list/CAFxXSLQb2u5qu0teDSjMNis_z--J7zYM6ppNqAdf2d%3DijDpcLA%40mail.gmail.com > <https://groups.google.com/d/msgid/everything-list/CAFxXSLQb2u5qu0teDSjMNis_z--J7zYM6ppNqAdf2d%3DijDpcLA%40mail.gmail.com?utm_medium=email&utm_source=footer> > . > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion visit https://groups.google.com/d/msgid/everything-list/CAMW2kAoAH2w3eDDw5u_UGmTmSHkhwFhtTPwk3VBXDnGoUJ2MJg%40mail.gmail.com.
